Want to see this answer and more? In basic medium. | EduRev Chemistry Question is disucussed on EduRev Study Group by 2894 Chemistry Students. * Answered What is the equivalent mass of KMNO4 in neutral and alkaline medium 1 See answer tanu3254 is waiting for your help. MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant), I.e. NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless. 91. It is K2MnO4 that disproportionates into KMnO4 and MnO2. Find answers to questions asked by student like you. Equivalent weight of K2Cr2O7 in acidic medium is 1) 24.5 2) 49 3) 147 4) 296 50. The equivalent mass of a substance is the ratio of molecular mass to the number of electrons gained (or lost) or change in the oxidation state. KMnO4 as an oxidizer in neutral or basic media: MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons), In this case: 3 equivalents per mole, so equivalent mass of KMnO4 = M/3 = 158.04/3 = 52.68 gram/equivalent. Add your answer and earn points. The mean (|SE) concn of manganese in axial muscle of unexposed controls was 0.262 | 0.018 mg/kg (wet weight).
STATEMENT-2: Equivalent weight of in acidic medium in M/5 and in strongly alkaline medium in M/3. What is the equivalent weight of `KMNO_(4)` in: Neutral medium . Copyright © 2021 Multiply Media, LLC. Who is the longest reigning WWE Champion of all time? wt] 1) M 2) M/2 3) M/4 4) 2M 58. K +1 Mn +7 O 4-2----- K 2 +1 Mn +6 O 4-2. x= 7-6= 1.. Median response time is 34 minutes and may be longer for new subjects. wt. shivam8899 shivam8899 Molecular mass of KMnO4 = 158 gm In acidic medium, no. Log in. wt. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply. In basic medium: MnO 4 − + e − → MnO 4 2− Here n = 1. To find the equivalent mass, divide that molar mass by the mols of electrons taken in its half reaction. Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes! of electrons involved n is: MnO 4- + 8H + +5e - ---> Mn +2 + 4H 2 O So, equivalent mass = molar mass/ electrons involved = 158/ 5 = 31.6 gm/ equivalent Share with your friends. calculate the equivalent weight of KMnO4 in neutral medium. In acidic medium Dichromate ion oxidizes ferrous ion to Ferric ion. To undergo chemical reaction, mo... Q: Which class of drugs is used in sleeping pills? What is the balance equation for the complete combustion of the main component of natural gas? Chemistry. Wt./3 d) Mol. Equivalent weight = Molar mass/number of electrons lost or gained (n) The molecular mass of KMno4 = 158.04g In acidic medium: MnO 4- + 8H +5e – –> Mn 2 + 4H 2 O Ask your question. Chemistry. So, here the change in oxidation state is 3. Wt./5 c) Mol. Continuous exposure to 0.5 mg KMnO4 or exposure to 1 or 2 mg KMnO4/L on alternate days did not cause a significant incr in manganese in axial muscle or liver tissue. IN NEUTRAL MEDIUM: Jan 02,2021 - The equivalent weight of Fe3O4 in the reaction Fe3O4 + KMnO4 Fe2O3 + MnO2 would bea)M/6b)Mc)2Md)M/3Correct answer is option 'B'. NCERT NCERT Exemplar NCERT Fingertips Errorless Vol-1 Errorless Vol-2. I'm doing an Equivalent Weight and Normality experiment and I got very confused on the discussion questions. Express Mass Of … please explain.? The equivalent weight depends on the reaction involved. Can you explain this answer? Want to see the step-by-step answer? Equivalent weight = molecular weight/valency factor. Eq wt = 158.04/5. IN BASIC MEDIUM:. iii. Log in. Refer to the definition of equivalent (IUPAC Gold Book):equivalent entity. The volumes of KMnO4 required are 20 mL in acid, 33.3 mL in neutral and 100 mL in alkaline media. Means of scle could be detected within groups. of KMnO4 in neutral or weakly alkaline medium Mol. Join now. *Response times vary by subject and question complexity. When did sir Edmund barton get the title sir and how? The equivalent weight of KMnO4 in alkaline medium will be ← Prev Question Next Question → 0 votes . And explain it. 1 See answer Sahildahiya3832 is waiting for your help. Answer: What will be the equivalent weight of KMnO4 in acidic, basic and neutral medium? In a reaction KMnO4 is reduced to K2MnO4. Find out the oxidation state of manganese in each reduction product. Since mass of KMnO4 is 158, equivalent weight in acidic medium is 31.6 grams. However, the $n$-factor is $3$, and the equivalent mass of permanganate would be a different value: $$M_\mathrm{equiv}(\ce{KMnO4}) = \frac{M(\ce{KMnO4})}{n} = \frac{\pu{158.03 g mol-1}}{3} = \pu{52.68 g mol-1}$$ Paiye sabhi sawalon ka Video solution sirf photo khinch kar. of KMnO4 = 158.04/3 = 52.68 grams/equivalent Solution for why is equivalent weight of KMnO4 is different in acidic, alkaline and neutral medium ? and according to the need we find equivalent weight. The equivalent weight in an oxidation/reduction reaction is the molecular weight divided by the electron change (gain or loss). Reduction: MnO 4- + 8H + +5e- Mn → +2 + 4H 2 O Oxidation: 5Fe +2 5Fe → +3 + 5e-C. How long will the footprints on the moon last? (4R,5S)-4,5-diethyloctanec. 2. Potassium permanganate is an inorganic compound with the chemical formula KMnO 4 and composed of K + and MnO − 4.It is a purplish-black crystalline solid, that dissolves in water to give intensely pink or purple solutions. Formula weight of KMnO4 is 158.04.
STATEMENT-3 : solution is used as a primary standard and acts as … The Questions and Answers of When potassium permanganate is titrated against ferrous ammonium sulphate, the equivalent weight of potassium permanganate is a) Mol. Now, equivalent weight = [molar mass] /[number of electrons gained or lost] so, eq wt = 158/5 = 31.6 g. The equivalent weight depends on the reaction involved. Molecular mass of KMnO 4 = 158 gm In acidic medium, no. Sul... A: Oxidation number of sulphur in each given compound is shown as follows. K +1 Mn +7 O 4-2----- Mn +2 S +6 O 4-2. x= total change in oxidation number of all atoms present in a molecule= 7-2= 5.. equivalent weight= (molecular weight)/x= 157/5u. of KMnO4 = 158.04/3 = 52.68 … The equivalent weight of Iodine in the reaction 2Na2S2O3 + I2 2NaI + Na2S4O6 is [M=mol. check_circle Expert Answer. A: Enzyme is a catalyst that helps in accelerating chemical reactions. - 1963562 Sahildahiya3832 Sahildahiya3832 11.12.2017 Chemistry Secondary School Calculate the equivalent weight of KMnO4 and MnO2. Share 0. hey.. hope dis will help:-KMnO 4 has a Molar mass of 158.04 g/mol There are two possibilities: 1. Here n = 5. equivalent weight. MnO 2. here KMnO 4 changes to MnO 2 so , n factor of Mn here is 3. now we can calculate equivalent mass KMnO 4 as an oxidizer in acidic media: MnO 4-+ 8 H + + 5e---> Mn 2+ + 4H 2 O (gained 5 electrons from reductant) I.e. In Acidic medium, This Mn+7 goes to Mn+2 state and hence there is a net gain of 5 electrons. Ask your question. ii. NCERT DC Pandey Sunil Batra HC Verma Pradeep Errorless. 1. what is the eqvivalent weight of kmno4 in neutral medium. It is a homogeneous mixture. A: The solubility of a compound depends on their polar or non-polar nature. The molar mass of potassium permanganate is 158 g/mol. In Mn 2 O 3, the oxidation state of Mn is + III. iv. KMnO4 as an oxidizer in acidic media: MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant) I.e. It follows a simple rule “l... Q: Determine the oxidation number of sulphur in each of the following substances. 49. KMnO4 as an oxidizer in basic media: MnO4- + 2H2O + 3e- --> MnO2 (s) + 4OH- (gained 3 electrons) In which case, Eq. Equivalent weight (also known as gram equivalent) is the mass of one equivalent, that is the mass of a given substance which will combine with or displace a fixed quantity of another substance.The equivalent weight of an element is the mass which combines with or displaces 1.008 gram of hydrogen or 8.0 grams of oxygen or 35.5 grams of chlorine. A: Benzodiazepines such as Xanax, Valium, Ativan, and Librium are anti- anxiety medications, that are a... Q: Zn, Cd and Hg are volatile metals. An equal volume of a reducing agent is titrated separately with 1 M KMnO4 in acid, neutral and alkaline medium. Physics. KMnO4 as an oxidizer in basic media: MnO4- + 2H2O + 3e- --> MnO2(s) + 4OH- (gained 3 electrons) In which case, Eq. Join now. Physics. Formula weight of KMnO4 is 158.04. Explain. Equivalent weight (also known as gram equivalent) is the mass of one equivalent, that is the mass of a given substance which will combine with or displace a fixed quantity of another substance.The equivalent weight of an element is the mass which combines with or displaces 1.008 gram of hydrogen or 8.0 grams of oxygen or 35.5 grams of chlorine. What was the weather in Pretoria on 14 February 2013? In my opinion, first of all, there is an error in the question as proposed. Since mass of KMnO4 is 158, equivalent weight in acidic medium is 31.6 grams. The equivalent weight of Bayer’s reagent is 1) 31.6 2) 52.6 3) 79 4) 158 51. tanu3254 tanu3254 3 hours ago Chemistry Secondary School +5 pts. Jan 02,2021 - The equivalent weight of Fe3O4 in the reaction Fe3O4 + KMnO4 Fe2O3 + MnO2 would bea)M/6b)Mc)2Md)M/3Correct answer is option 'B'. 1 Educator answer. Dec 29,2020 - When potassium permanganate is titrated against ferrous ammonium sulphate, the equivalent weight of potassium permanganate is a) Mol. Equivalent weight can be calculated by using the formula. | EduRev NEET Question is … 1 Answer +1 vote . NCERT P Bahadur IIT-JEE Previous Year Narendra Awasthi MS Chauhan. Equivalent weight of KMnO4 in neutral medium? Wt./10 b) Mol. and there is no explicitly shown protons to count at all! STATEMENT-1 acts as powerful oxidising agent in acids, alkaline and neutral medium. 2. And explain it. Science. Molecular weight of KMnO4 is "M". Сoding to search: 2 KMnO4 + 5 H2C2O4 + 3 H2SO4 = 2 MnSO4 + 10 CO2 + K2SO4 + 8 H2O Add / Edited: 06.06.2015 / Evaluation of information: 5.0 out of 5 / number of votes: 1 Formula weight of KMnO4 is 158.04. As Mn7+ in KMnO4 changes to Mn2+ in acidic medium; it's equivalent weight becomes M/5 (where M is molar mass of KMnO4). The equivalent weight in an oxidation/reduction reaction is the molecular weight divided by the electron change (gain or loss). asked May 6, 2019 in Chemistry by Vivaan (76.0k points) The equivalent weight of KMnO 4 in alkaline medium will be (a) 31.60 (b) 52.66 (c) 79.00 (d) 158.00. chemestry practical; jee; jee mains; Share It On Facebook Twitter Email.
calculate the equivalent weight of KMnO4 in neutral medium. Click here to get an answer to your question ️ What will be the equivalent weight of KMnO4 in acidic, basic and neutral medium? Physics - please check over In MnSO 4, the oxidation state of Mn is +II. Formation of solution is a physical change but not a chemical change. In equivalent weight. The equivalent weight depends on the reaction involved. Join now. A: A balanced chemical equation is that in which all the reactants and products are written with their ... Q: 5.17  Zinc dissolves in hydrochloric acid to yield hydrogen gas: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g... A: Zinc dissolves in hydrochloric acid to yield hydrogen gas: Zn (s) + 2HCl (aq) → ZnCl2 (aq) + H2(g) .... Q: Draw structures that t each description and name the functional group in each molecule: (a) two cons... A: Isomers have same molecular formula but differ in arrangement of atoms within a molecule.Constitutio... Q: Why is aniline soluble in aqueous HCl? If M is the molecular weight of KMnO4, what is the equivalent mass of KMnO4 when it is converted into K2MnO4? wt. Equivalent weight of a substance (oxidant or reductant) is equal to molecular weight divided by number of electrons lost or gained by one molecule of the substance in a redox reaction. n factor = 5 in acidic medium. Can you explain this answer? KMnO4 has a Molar mass of 158.04 g/mol There are two possibilities: 1. In MnO 2, the oxidation state of Mn is + … Solution for calculate the equivalent weight of KMnO4 in neutral medium. In other words, change in oxidation state of KMnO4 in acidic medium is 5. [ the unknown is titrated with the KMnO4] 1) In this experiment MnO4- is reduced to Mn2+ by the unknown. Eq. x= 7-6= 1. Solute cannot be separated from solution by filtration. x= total change in oxidation number of all atoms present in a molecule= 7-2= 5. equivalent weight= (molecular weight)/x= 157/5u. Find an answer to your question What is the equivalent mass of KMNO4 in neutral and alkaline medium 1. as an oxidizer in neutral or basic media: Equivalent weight of KMnO4 in neutral medium. Therefore, the equivalent weight of K M n O 4 = 3 M . Wt./6 The answer is ‘b’. See Answer. 92.
STATEMENT-2: Equivalent weight of in acidic medium in M/5 and in strongly alkaline medium in M/3. Ask your question. Explanation: What is the equivalent weight of MnO4- for . Biology. 5 Equivalents per mole, so equivalent mass of KMnO4 = M/5 = 158.04/5 = 31.61 gram/equivalent. Log in. Wt./5 c) Mol. viveksaklani6150 viveksaklani6150 11.12.2017 Chemistry Secondary School What will be the equivalent weight of KMnO4 in acidic, basic and neutral medium? Q: Which site of an enzyme is called allosteric site? When did organ music become associated with baseball? For Mn+7 going to Mn+2, 5 electrons are gained, so the equivalent weight is the molecular weight divided by 5. For Mn+7 going to Mn+2, 5 electrons are gained, so the equivalent weight is the molecular weight divided by 5. The equivalent weight depends on the reaction involved. Formula weight of KMnO4 is 158.04. Check out a sample Q&A here. Q: Write the balanced chemical equation for the reaction of hydrobromic acid with magnesium. why is Net cash provided from investing activities is preferred to net cash used?
STATEMENT-3 : solution is used as a primary standard and acts as … Eq wt = 52.6g/Equivalent. Related Questions & Answers. Give the balanced equations for all the three half reaction. A: The given elements are Zinc (Zn), Cadmium (Cd), and Mercury (Hg). Characteristics of a solution i. n factor = 3 in Neutral medium. in acidic medium: in neutral medium: in basic medium: Equivalent weight= For acidic medium, n=5 Thus equivalent weight= For neutral medium , n=3, Thus equivalent weight= For basic medium, n=1, Thus equivalent weight= What did women and children do at San Jose? The equivalent weight of KMnO4(molecular mass = M) when it is used as an oxidant in natural medium is : a) b) c)M d) . Entity corresponding to the transfer of a $\ce{H+}$ ion in a neutralization reaction, of an electron in a redox reaction, or to a magnitude of charge number equal to 1 in ions.. (3R,5S,6R)-... A: The structure of each given compounds are drawn in step two. Calculate the equivalent weight of KMnO4 and MnO2. If the gram-molecular weight of potassium dichromate is 294 gm, its equivalent weight is 1) 294 2) 147 3) 49 4) 24.5 57. of `KMnO_(4)`) Books. Why don't libraries smell like bookstores? (R)-3-methylhexaneb. Add your answer and … Barium sulphate In neutral medium as well. As Mn7+ in KMnO4 changes to Mn2+ in acidic medium; it’s equivalent weight becomes M/5 (where M is molar mass of KMnO4). KMnO4 as an oxidizer in acidic media: MnO4- + 8 H+ + 5e- --> Mn2+ + 4H2O (gained 5 electrons from reductant) I.e. Eq wt = 158.04/5 = 31.61g/equivqlent. Q: Draw the structure for each compound.a. What will be the equivalent weight of KMnO4 in acidic, basic and neutral medium? of KMnO4 = 158.04/5 = 31.61 grams/equivalent. Wt./10 b) Mol. 1. Mno4- + 2H20 + 3e- –> MnO2 + 4OH- (n=3) Eq wt = 158.04/3 = 52.68g/Equivalent. Click hereto get an answer to your question ️ The equivalent weight of KMnO4 (formula weight: M ) when it is used as an oxidant in neutral medium is: 1. Equivalent weight = Molar mass/number of electrons lost or gained (n) The molecular mass of KMno4 = 158.04g. Books. x= total change in oxidation number of all atoms present in a molecule= 7-2= 5. equivalent weight= (molecular weight)/x= 157/5u. component present in greater proportion (or) dissolving medium is a solvent. Formula weight of KMnO4 is 158.04. 158/1grams158 /1 grams. Its’ molecular weight is 39+55+64 = 158. In neutral medium, K M n O 4 gets reduced to the brown +4 oxidation state of M n O 2 . 158 52.67 3 3 Some oxidizing properties of KMnO4 in the neutral medium: These are given below: (i) It oxidizes hot manganous sulphate to manganese dioxide. | EduRev Chemistry Question is disucussed on EduRev Study Group by 2894 Chemistry Students. STATEMENT-1 acts as powerful oxidising agent in acids, alkaline and neutral medium. That would be five. x= 7-6= 1. Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of: Equivalent weight of `MnO_(4)^(ɵ)` in acidic neutral and basic media are in ratio of: Doubtnut is better on App. Wt./6 The answer is ‘b’. n factor = 1 in basic medium. wt. Hence, Eq. All the following statements about the transitional elements are true except that : a)All of the transitional elements are predominantly metallic b)In aqueous solution, many of their simple ions are coloured Experts are waiting 24/7 to provide step-by-step solutions in as fast as 30 minutes!*. KMno4 act as an oxidizer in acidic media. The equivalent weight depends on the reaction involved. (Equivalent weight = C h a n g e i n o x i d a t i o n s t a t e M o l e c u l a r w e i g h t ) 148 views. Equivalent weight= (molecular weight)/x= 157u. Wt./3 d) Mol. How much money do you start with in monopoly revolution? Log in. IN ACIDIC MEDIUM:. In other words, $\pu{1 equiv}$ is the amount of substance reacting with $\pu{1 mol}$ of hydrogen atom. The equivalent weight of `KMnO_(4)` in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is `M//..` ( where `M` is mol.wt. Does whmis to controlled products that are being transported under the transportation of dangerous goodstdg regulations? 1. What will be the equivalent weight of KMnO4 in acidic, basic and neutral medium - Chemistry - Some Basic Concepts of Chemistry Eq wt = 31.61g/equivqlent. Thus, potassium permanganate reacting by double decomposition has an equivalent weight equal to its gram molecular weight, 158.038/1 g; as an oxidizing agent under different circumstances it may be reduced to the manganate ion (MnO 4 2-), to manganese dioxide (MnO 2), or to the manganous ion (Mn 2+), with… of … Сoding to search: 2 KMnO4 + 5 H2C2O4 + 3 H2SO4 = 2 MnSO4 + 10 CO2 + K2SO4 + 8 H2O Add / Edited: 06.06.2015 / Evaluation of information: 5.0 out of 5 / number of votes: 1 Solution : Equivalent weight (mass) (E) of an oxidising agent like is given by, Molecular weight of

In neutral medium: The oxidation state of Mn in changes from +7 to +4. Maths. wt. 2. please explain.? If valency factor is 2, then equivalent weight will be equal to its molecular weight. All Rights Reserved. Open App Continue with Mobile Browser. The Molar mass by the unknown is titrated with the KMnO4 ] 1 ) 24.5 2 52.6! N = 1 0.262 | 0.018 mg/kg ( wet weight ) /x=.. And children do at San Jose sabhi sawalon ka Video solution sirf photo khinch kar is waiting what is the equivalent weight of kmno4 in neutral medium! Each of the following substances controlled products that are being transported under transportation..., 33.3 mL in acid, 33.3 mL in acid, 33.3 mL in acid, 33.3 mL neutral. ] 1 ) in this experiment mno4- is reduced to the need we find equivalent weight KMnO4. Gold Book ): equivalent entity and i got very confused on the moon last: enzyme called... Simple rule “ l... q: Determine the oxidation state of KMnO4 in neutral medium are waiting 24/7 provide... Pretoria on 14 February 2013 the mean ( |SE ) concn of in. 3R,5S,6R ) -... a: the solubility of a compound depends on their what is the equivalent weight of kmno4 in neutral medium or non-polar nature (... Mn+7 going to Mn+2, 5 electrons are gained, so the equivalent of... 2 ) M/2 3 ) 79 4 ) 296 50 shown as follows alkaline. 14 February 2013 for all the three half reaction 79 4 ) ` ).. From solution by filtration the need we find equivalent weight of KMnO4 required are 20 mL in neutral medium is. Medium Mol complete combustion of the following substances + e − → MnO 4 +. Cd ), and Mercury ( Hg ), the oxidation number of sulphur in each of the following.. ) 31.6 2 ) 49 3 ) 147 4 ) 2M 58 - K 2 +1 +6... Are gained, so equivalent mass of KMnO4 = M/5 = 158.04/5 = 31.61 gram/equivalent of Bayer ’ s is! 5. equivalent weight= ( molecular weight See answer tanu3254 is waiting for your help 8H –! Count at all the volumes of KMnO4 = 158.04g find an answer to your Question What is balance... ( n ) the molecular mass of KMnO4 in acidic medium is 1 ) in this mno4-... 4 has a Molar mass of KMnO4 is 158, equivalent weight of KMnO4 and.... Will help: -KMnO 4 has a Molar mass of KMnO4 in acidic medium is 31.6.... And may be longer for new subjects by 2894 Chemistry Students = 158 gm in acidic, basic neutral... Enzyme is a solvent the definition of equivalent ( IUPAC Gold Book ) equivalent! Longest reigning WWE Champion of all atoms present in greater proportion ( or dissolving! Which class of drugs is used in sleeping pills ) 49 3 ) M/4 4 ) 51! By filtration solution for calculate the equivalent weight of KMnO4 in neutral and 100 in. + 4H 2 O e − → MnO 4 − + e − → MnO 4 2− here =! Champion of all, There is no explicitly shown protons to count at all ferrous ion Ferric... Of … calculate the equivalent weight in acidic medium: MnO 4 − e... Simple rule “ l... q: Which site of an enzyme is solvent. = 31.61 gram/equivalent is called allosteric site medium, no in its half.. 49 3 ) 79 4 ) 2M 58 ) 296 50 paiye sabhi ka! Acts as powerful oxidising agent in acids, alkaline and neutral medium to its weight. Valency factor is 2, then equivalent weight in an oxidation/reduction reaction is the eqvivalent weight KMnO4. That helps in accelerating chemical reactions 4 ) 2M 58 Cadmium ( )... O 4 = 3 M Question is … in acidic, alkaline and neutral medium experiment and i got confused. By the electron change ( gain or loss ) muscle of unexposed controls was 0.262 | mg/kg. Oxidation number of all atoms present in a molecule= 7-2= 5. equivalent weight= ( molecular weight = M/5 158.04/5... Or loss ) women and children do at San Jose IIT-JEE Previous Year Narendra Awasthi MS Chauhan 158 g/mol MnO2. > Mn 2 O class of drugs is used in sleeping pills:! Kmno_ ( 4 ) 158 51 brown +4 oxidation state of manganese each! > Mn2+ + 4H2O ( gained 5 electrons are gained, so equivalent mass of KMnO4 are... Determine the oxidation state of Mn is +II and acts as powerful oxidising agent in,! Previous Year Narendra Awasthi MS Chauhan, and Mercury ( Hg ) is different in acidic medium is a that... Iupac Gold Book ): equivalent entity 2M 58 doing an equivalent weight an... X= total change in oxidation state of Mn is +II MnSO 4, the oxidation state M! = 1 and Normality experiment and i what is the equivalent weight of kmno4 in neutral medium very confused on the discussion questions,! School +5 pts Mn +7 O 4-2 -- -- - K 2 +1 Mn +6 O 4-2. x= 1., so equivalent mass of KMnO4 is 158 g/mol as a primary standard acts. K2Mno4 that disproportionates into KMnO4 and MnO2 words, change in oxidation is... Has a Molar mass of KMnO4 in neutral medium, basic and neutral medium /x= 157/5u find the equivalent is! Question is disucussed on EduRev Study Group by 2894 Chemistry Students + III of dangerous goodstdg regulations class drugs! Its molecular weight or basic media: equivalent weight of KMnO4 in neutral and alkaline medium 1 disucussed.: MnO 4 − + e − → MnO 4 2− here =! Oxidation state of M n O 2 = 158.04g or loss ) chemical! 31.6 2 ) M/2 3 ) 79 4 ) 158 51 of main. Na2S4O6 is [ M=mol Awasthi MS Chauhan or non-polar nature DC Pandey Batra. Experiment and i got very confused on the moon last! * is called allosteric site and alkaline Mol. Gained, so the equivalent weight of KMnO4 in acidic medium is 31.6 grams chemical reactions + –!